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7k^2-9k-8=0
a = 7; b = -9; c = -8;
Δ = b2-4ac
Δ = -92-4·7·(-8)
Δ = 305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{305}}{2*7}=\frac{9-\sqrt{305}}{14} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{305}}{2*7}=\frac{9+\sqrt{305}}{14} $
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